17x^2/20=x

Solution for 17x^2/20=x equation:

17x^2/20=x

We move all terms to the left:

17x^2/20-(x)=0

We add all the numbers together, and all the variables

17x^2/20-1x=0

We multiply all the terms by the denominator


17x^2-1x*20=0

Wy multiply elements

17x^2-20x=0

a = 17; b = -20; c = 0;
Δ = b2-4ac
Δ = -202-4·17·0
Δ = 400
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{400}=20$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-20}{2*17}=\frac{0}{34}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+20}{2*17}=\frac{40}{34}
=1+3/17
$